10(X^2+4x+4)=40x+80

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Solution for 10(X^2+4x+4)=40x+80 equation: 


Simplifying
10(X2 + 4x + 4) = 40x + 80

Reorder the terms:
10(4 + X2 + 4x) = 40x + 80
(4 * 10 + X2 * 10 + 4x * 10) = 40x + 80
(40 + 10X2 + 40x) = 40x + 80

Reorder the terms:
40 + 10X2 + 40x = 80 + 40x

Add '-40x' to each side of the equation.
40 + 10X2 + 40x + -40x = 80 + 40x + -40x

Combine like terms: 40x + -40x = 0
40 + 10X2 + 0 = 80 + 40x + -40x
40 + 10X2 = 80 + 40x + -40x

Combine like terms: 40x + -40x = 0
40 + 10X2 = 80 + 0
40 + 10X2 = 80

Solving
40 + 10X2 = 80

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + 10X2 = 80 + -40

Combine like terms: 40 + -40 = 0
0 + 10X2 = 80 + -40
10X2 = 80 + -40

Combine like terms: 80 + -40 = 40
10X2 = 40

Divide each side by '10'.
X2 = 4

Simplifying
X2 = 4

Take the square root of each side:
X = {-2, 2}

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